Wednesday, February 15, 2017

Chapter 8 - Carbon and it's compounds

In the previous section, we completed the discussion on the compounds of some non-metals. In this section we will discuss about Carbon and it's compounds.

Importance of Carbon

• We know that all substances around us are made up of chemical compounds. 
• These chemical compounds are made up of elements. 
■ If we make a list of ten things that we use in our day to day life, most of the items in that list will contain carbon.

Food items, clothes, oils, soaps, cosmetics, fuels, paints, rubber, paper etc., are all made up of compounds of carbon. In addition to this, plant and animal bodies are made up of carbon compounds. New compounds of carbon are being discovered or created artificially almost every day.

Bonding between atoms in carbon compounds

We know that, any compound will have atoms of various elements. A carbon compound will have atoms of carbon and one or more other elements. The other elements may be hydrogen, oxygen, chlorine etc., Now we will discuss how the atoms are held together in a molecule of a carbon compound.

The atomic number of carbon is 6. It's electronic configuration is 2,4. So it will have 4 valence electrons. 
To attain the stable electronic configuration: 
• the carbon should lose the 4 electrons. 
• or, it should gain 4 new electrons. 
Both the above options are difficult. Let us see the reason:
■ A large amount of energy will be required to remove the four valence electrons. Even if they are removed, the 6 protons in the nucleus will be attracting just 2 electrons. This is not possible. So, removal of 4 electrons will not occur
■ If the carbon atom is to gain 4 electrons, the 6 protons in the nucleus will have to attract and hold 10 electrons in the shells. This is difficult. So gaining of electrons also will not occur

What occurs is the sharing of electrons. This will give rise to covalent bonds between carbon atom and atoms of other elements. We have seen the details about covalent bonds earlier. Let us now draw the covalent bonds in some of the carbon compounds:
■ First we will take Methane (CH4)
We have already seen it when we discussed about covalent bond. The details are presented here again.
• Carbon has an atomic number 6. It’s electronic configuration is 2,4. It has 4 electrons in the outer most shell. It needs four more electrons to attain octet. 
• Hydrogen has an atomic number 1. It’s electronic configuration is also 1. It has 1 electron in the outer most shell. It needs one more electron to attain octet.
• We see that both carbon and hydrogen are in ‘need for electrons’. They cannot donate any electrons. So the only solution is to form a covalent bond as shown in fig.8.1 below:
Fig.8.1
• The details about this bond can be written as:
• One carbon atom combines with 4 hydrogen atoms. Each of the four hydrogen atoms share one pair of electrons with the carbon atom
• In total, four pairs (that is., eight electrons) are shared. The eight electrons in the pairs, belongs to both the carbon atom and the hydrogen atom.
• The carbon atom now has the required four electrons for octet. 
• The hydrogen atom now has the required 2 electrons for octet
• As the pair belongs to both the atoms, they will not be able to move away from each other
• That is., the carbon and four hydrogen atoms will have to always stick together. Thus a bond is formed between the five atoms
• In each bond, there is a sharing of one pair of electrons. So each bond is a 'single bond'. So methane can be represented as shown in fig.8.2(a) below. The 'single lines' between C and H indicates 'single bonds'.
Fig.8.2
■ Next we will consider Carbon dioxide (CO2)
• Carbon has an atomic number 6. It’s electronic configuration is 2,4. It has 4 electrons in the outer most shell. It needs four more electrons to attain octet. 
• Oxygen has an atomic number 8. It’s electronic configuration is 2,6. It has 6 electrons in the outer most shell. It needs two more electrons to attain octet.
• We see that both carbon and oxygen are in ‘need for electrons’. They cannot donate any electrons. So the only solution is to form a covalent bond as shown in fig.8.3 below:
Fig.8.3
• The details about this bond can be written as:
• One carbon atom combines with 2 oxygen atoms. Each of the two oxygen atoms share two pairs of electrons with the carbon atom
• In total, four pairs (that is., eight electrons) are shared. The eight electrons in the pairs, belongs to both the carbon atom and the oxygen atoms.
• The carbon atom now has the required 4 electrons for octet. 
• The oxygen atoms now has the required 2 electrons for octet
• As the pair belongs to both the atoms, they will not be able to move away from each other
• That is., the carbon and two oxygen atoms will have to always stick together. Thus a bond is formed between the three atoms
• In each bond, there is a sharing of two pairs of electrons. Thus each bond is a 'double bond'. So carbon dioxide can be represented as shown in fig.8.2(b) above. The 'double lines' between C and O indicates 'double bonds'.

A very large number of carbon compounds

We have seen that many objects that use in our day to day life are made up of carbon compounds. The number of carbon compounds was recently estimated to be nearly three million. That is., thirty lakhs. This is far greater than the total number of compounds formed by all other elements.

How is it possible for the carbon to form such large number of compounds? 
Let us analyse the reasons:
Reason 1
We know that carbon has 4 electrons in it's outer most shell. That is., it has a valency of 4. This makes it possible to form 3 different types of bonds. They are shown in fig.8.4 below:
Fig.8.4
• In the fig., the green dots indicate the electrons already possessed by the carbon atom. 
• The red dots indicate the new electrons which are acquired by sharing.
Let us see each type in detail:
1. In fig.8.4(a), the carbon is in bond with 4 other atoms. Each bond is a single bond. Through this arrangement, 4 new electrons are acquired. Thus octet is achieved.
2. In fig.b, the carbon is in bond with 3 other atoms. The bond with one of them is a double bond. Through this arrangement, 4 new electrons are acquired. Thus octet is achieved.
3. In fig.c, the carbon is in bond with 2 other atoms. The bond with one of them is a triple bond. Through this arrangement, 4 new electrons are acquired. Thus octet is achieved.
■ Thus there are three methods by which a carbon atom can enter into bond with others. The bonds so formed are very strong. The reason for the strong bonds can be explained as follows:
• The size of a carbon atom is small. So the force of attraction between the central nucleus and the outer most electrons will be strong. This gives strong bonds. So the molecules thus formed are very stable. 
The chemical properties of the newly formed molecules will depend upon the properties of carbon and also the newly bonded elements.
Reason 2
Carbon has the unique ability to enter into bondage with other carbon atoms. 
• Because of this ability, long chains of carbon atoms can be formed. This is shown in fig.8.5(a) below:
Fig.8.5
 • From a chain, another chain can branch off as shown in fig.b.
• The end carbon in a chain may enter into bondage with the first carbon to form a ring. This is shown in fig.c.
■The ability of atoms of an element to combine among themselves and form chains is called catenation.  Chains, branched chains and rings are formed because of this property. 
• Carbon has the ability to catenate. 
• But it is not seen in other elements. Silicon some times forms chains up to a maximum of  8 atoms long. But the molecules thus formed are very reactive. 
• We have seen that the carbon bond is very strong and hence stable. So a large variety of carbon compounds are possible. 


So we have seen two reasons. The formation of very large number of carbon compounds can be explained using those two reasons.

In the next section, we will see the actual arrangement of atoms in a molecule of Carbon compounds. 

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Monday, February 6, 2017

Chapter 7.3 - Nitric acid

In the previous section, we discussed about Hydrogen chloride. In this section we will discuss about Nitric acid.


Nitric acid

Nitric acid is another industrially important compound. One of it's main uses is in the production of chemical fertilizers.
Nitric acid is produced in the laboratory by heating potassium nitrate and concentrated sulphuric acid in a retort. The arrangement is shown in the fig.7.5 below:
Fig.7.5
The equation of the reaction is:
KNO3 + H2SO4 → KHSO4 + HNO3. This is a balanced equation.

• Nitric acid is a volatile acid. That means, it easily changes to gaseous state from liquid state. So cold water is used to cool the vapours. When the vapours are cooled, they condense, and turn into liquid nitric acid.
• Pure nitric acid is a colourless liquid. But the nitric acid obtained in the laboratory is pale yellow in colour. Let us see the reason:
Nitric acid dissociates to produce nitrogen dioxide (NO2) gas. Let us write the equation for this dissociation: 4HNO3 → 4NO2 + 2H2O + O2.
The nitrogen dioxide thus produced is reddish brown in colour. This nitrogen dioxide dissolves in the acid, and as a  thus the acid becomes pale yellow in colour.

Industrial production of nitric acid 

This is possible through Ostwald process. This process was designed by the German scientist Wilhem Ostwald in 1932. Let us see the various stages in this process:
Stage 1: Ammonia and oxygen reacts together to form nitric oxide. Platinum is used as a catalyst in this reaction. The equation is: 4NH3 + 5O2 → 4NO + 6H2O.
Stage 2: The nitric oxide reacts with oxygen to produce nitrogen dioxide. The equation is:
2NO + O2 → 2NO2.
Stage 3: The nitrogen dioxide is dissolved in water, in the presence of oxygen to produce nitric acid.
The equation is: 4NO2 + 2H2O + O2 → 4HNO3.

Reaction of nitric acid with metals
• We have seen that hydrochloric acid reacts with metals and produce hydrogen. Details here.
• The nitric acid also reacts with metals. But the products will depend upon the concentration of the acid, and also on the nature of the metal

Identification of nitrate salts

1. Take the aqueous solution of the given salt in a test tube. 
2. Add equal volume of freshly prepared ferrous sulphate solution to it and mix well. 
3. Hold the test tube containing the  mixture in a slanting position. 
4. Slowly pour concentrated sulphuric acid along the sides of the test tube. 
5. If a brown ring is formed at the junction of the two liquids, the salt can be confirmed as a nitrate.

Note that it is very important to handle acids carefully. All safety measures should be taken. Some of the compulsory safety measures are:
• Wearing lab coat or lab apron
• Wearing safety goggles for protection of eyes
• Using acid resistant gloves
Experiments should be performed only under the guidance of authorised professionals


A video showing the procedure can be seen here.


Uses of nitric acid


• In the manufacture of fertilizers • As an oxidising agent in rocket fuels • In the purification of gold • For etching alphabets and pictures on metals • To prepare aqua regia used for dissolving noble metals


Aqua regia is a mixture of concentrated nitric acid and concentrated hydrochloric acid. They are taken in the ratio 1:3. That is., if we take 5 ml of nitric acid, we must take 15 ml of hydrochloric acid. This mixture can dissolve noble metals like gold and platinum. Let us see how this is possible:
The equation for the reaction is:
HNO3 + 3HCl →  2H2O. + NOCl + 2[Cl]
The chlorine atoms thus liberated, will react with gold, platinum etc., forming their chlorides and thus dissolving them.

In the next section, we will see Carbon. 

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Monday, January 30, 2017

Chapter 7.2 - Preparation and Properties of Hydrogen chloride

In the previous section, we discussed about sulphuric acid. In this section we will discuss about Hydrogen chloride.


Hydrogen chloride

Hydrogen chloride is an important compound of hydrogen and chlorine. The preparation of hydrogen chloride in the laboratory is shown in fig.7.3 below:
Fig.7.3
The reactants used are sodium chloride (NaCl) and concentrated sulphuric acid. First, NaCl is taken in a flask. Then the concentrated sulphuric acid is added through the thistle funnel. The mixture is heated. Equation of the reaction is:
NaCl + H2SO4 → NaHSO4 + HCl. This is a balanced equation
• The HCl gas formed is passed through concentrated sulphuric acid. Why is this?
We know that concentrated sulphuric acid is a drying agent. We have seen the details here. So we will get dry HCl in the gas jar.
• HCl gas is denser than air. So it will be collected in the gas jar by the upward displacement of air.
• HCl gas is colourless. So how do we know whether the gas jar is full or not? The method is as follows:
We know that:
    ♦ Acids turn blue litmus paper red
    ♦ Bases turn red litmus paper blue
HCl is acidic. So show a wet blue litmus paper at the mouth of the gas jar. If the gas jar is full, the HCl gas will come in contact with the litmus paper, and it's colour will become red.


Solubility of Hydrogen chloride gas in water

• We have seen the fountain experiment for ammonia gas. Details here. It proved that the ammonia gas is soluble in water. 
• The same experiment can be used to prove the solubility of HCl gas in water. The apparatus is shown in the fig.7.4 below:
Fig.7.4
• The only difference is that, blue litmus is added to the water in the trough. This blue colour will change to red colour when it becomes the fountain. We can explain this colour change as follows:
When the water enters the flask, the HCl gas will dissolve in it. The water will thus become acidic. But blue litmus is already added to the water. So this blue colour will change to red. Thus we get a red coloured fountain.

Properties of Hydrogen chloride gas

• It is a colourless gas • It has a pungent smell • It is denser than air • It is soluble in water • It is acidic in nature

Identification of hydrogen chloride gas

Introduce a glass rod dipped in ammonia solution to the HCl gas. Thick white fumes of ammonium chloride shows the presence of HCl gas. The fumes are due to the formation of ammonium chloride (NH4Cl). The equation of the reaction is:
NH3 + HCl → NH4Cl
This is a balanced equation
■ Note that the same reaction was used earlier in the identification of ammonia. Details here. 
• There we dipped the glass rod in ammonia and introduced it to HCl
• Here we dip the glass rod in HCl and introduce it to ammonia

Hydrochloric acid

• The aqueous solution of hydrogen chloride gas is hydrochloric acid. Molecular formula of hydrochloric acid is HCl. 
• It is a volatile acid. That is., the acid will easily change to gaseous state. If the bottle containing concentrated HCl is kept open, white fumes will be formed. This is due to the dissolution of HCl gas in the water vapour of the air. A video can be seen here.

Some reactions of hydrochloric acid:
HCl reacts with almost all metals and metallic compounds. Let us see some examples:
■ Reaction with the metal zinc:
• We have seen the above reaction in the preparation of hydrogen. Details here.
• The balanced equation is: Zn + 2HCl → ZnCl2 + H2 .
• So, when HCl reacts with a metal, two things happen:
    (i) The chloride of the metal is formed
    (ii) Hydrogen is formed
■ Reaction with sodium hydroxide:
We have seen the above reaction when we learned neutralisation. Details here.
■ Reaction with calcium carbonate:
• This reaction gives calcium chloride. The balanced equation is:
2HCl + CaCO3 → CaCl2 + H2O + CO2.

Identification of chloride salts

The following procedure can be used:
1. Make an aqueous solution of the given salt.
2. Add a little silver nitrate (AgNO3) solution to this
3. If a curdy white precipitate is formed, the given salt can be a chloride salt. The balanced equation is:
NaCl + AgNO3 → AgCl ↓ +  NaNO3.
4. But we need to confirm. For that, add ammonium hydroxide solution to the white curdy precipitate

5. If the white precipitate dissolves, we can confirm that, the given salt is a chloride salt.
A video showing the formation of white curdy precipitate can be seen here.

In the next section, we will see Nitric acid. 

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